Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to n. There are n buttons in Mashmokh's room indexed from 1 to n as well. If Mashmokh pushes button with index i, then each light with index not less than i that is still turned on turns off.
Mashmokh is not very clever. So instead of pushing the first button he pushes some of the buttons randomly each night. He pushed mdistinct buttons b1, b2, ..., bm (the buttons were pushed consecutively in the given order) this night. Now he wants to know for each light the index of the button that turned this light off. Please note that the index of button bi is actually bi, not i.
Please, help Mashmokh, print these indices.
The first line of the input contains two space-separated integers n and m (1 ≤ n, m ≤ 100), the number of the factory lights and the pushed buttons respectively. The next line contains m distinct space-separated integers b1, b2, ..., bm (1 ≤ bi ≤ n).
It is guaranteed that all lights will be turned off after pushing all buttons.
Output n space-separated integers where the i-th number is index of the button that turns the i-th light off.
5 44 3 1 2
1 1 3 4 4
5 55 4 3 2 1
1 2 3 4 5
In the first sample, after pressing button number 4, lights 4 and 5 are turned off and lights 1, 2 and 3 are still on. Then after pressing button number 3, light number 3 is turned off as well. Pressing button number 1 turns off lights number 1 and 2 as well so pressing button number 2 in the end has no effect. Thus button number 4 turned lights 4 and 5 off, button number 3 turned light 3 off and button number 1 turned light 1 and 2 off.
这套题真是考验英语水平。。。。
#include#include #include #include #include #include using namespace std;typedef long long ll;int a[105],b[105]={0};int main(){ int n,m; cin>>n>>m; for(int i=0;i >a[i]; for(int j=a[i];j<=n;j++) if(b[j]==0) b[j]=a[i]; else break; } for(int i=1;i<=n;i++) cout< <<' '; cout<
读半天题目都没读懂真是醉了。。。。。。。说一下题意:每天得到ai个可以转换钱的东西(可以比喻成银行卡啥的),只不过这个东西只能当天去换钱,不能每天攒到一起了凑整别的天再去换,换得[w*a/b]块钱,方括号表示取整,可是这个人虽然喜欢这个卡,但是毕竟更喜欢money呀!!所以呢,在换得最大钱数的情况下,有一些卡是可以留下来积攒的,所以让我们求每天最多可以积攒多少这种卡?很简单吧!可是读题是硬伤T_T……
#include#include #include #include #include #include using namespace std;typedef long long ll;ll x;int main(){ int n;ll a,b; cin>>n>>a>>b; for(int i=0;i >x; ll tem=x*a/b; //cout<